Two vertices of triangle are (-2,-1) and (3,2) and third vertex lies on the line `x+y=5.` If the area of the triangle is 4 square units, then the third vertex is a. (-0,50 or (4,1) b. (5,0) of (1,4) c. (5,0) or (4,1) d. (o,5) or (1,4)

Explanation

Let` (h, k) `be the third vertex of the triangle


It is given that the area of the triangle with vertices` (h, k), (-2, -1) and (3, 2)` is `4` square units.


`(1/2)h(−1−2)−3(−1−k)−2(2−k)=4`


`\Rightarrow 3h−5k+1=±8`

Taking positive sign, we get,

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