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(i) Find the gradient of a straight line...

(i) Find the gradient of a straight line which is passes through the point (-3. 6) and the mid point of (4,-5) and (-2, 9)

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The coordinates of the mid-point` D `of the segment `BC` are `(1,2).`
`\therefore` Slope of `A D=\frac{6-2}{-3-1}=-1`
`\Rightarrow \theta=-1`, where `\theta` is the angle made by` AD` with `x`-axis
`\Rightarrow \theta=\frac{3 \pi}{4}`
So, `AD` makes angles `\frac{3 \pi}{4} `with `x`-axis
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