A point equidistant from the line `4x+3y+2=0,\ 5x-12 y+26=0\ a n d\ 7x+24 y-50=0` is `(1,-1)` b. `(1,1)` c. `(0,0)` d. `(0,1)`

Explanation

Let the co-ordinates of the point be` (a, b)`


Now, the distance of the point `(a, b)` from` 4 x+3 y+10=0 `is given by



`\Rightarrow|\frac{4 a+3 b+10}{\sqrt{4^{2}+3^{2}}}| `


`\Rightarrow|\frac{4 a+3 b+10}{5}|`

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