Find the ratio in which the line `3x+4y+2=0` divides the distance between the lines `3x+4y+5=0a n d3x=4y-5=0.`

Explanation

Lines` 3 x+4 y+2=0 \ 3 x+4 y+5=0 `are on the same side of the origin. The distance between these Iines is


`d_{1}=|\frac{2-5}{\sqrt{3^{2}+4^{2}}}|=\frac{3}{5}`


Lines `3 x+4 y+2=0` and` 3 x+4 y-5=0` are on the opposite sides of the origin. The distance between these lines is



`{d}_{2}=|\frac{2+5}{\sqrt{3^{2}+4^{2}}}|=\frac{7}{5}`
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