The coordinates of the foot of the perpendicular from the point (2,3) on the line `x+y-11=0` are `(-6,5)` b. `(5,6)` c. `(-5,6)` d. `(6,5)`

Explanation

Now, `x+y-11=0`

`\Rightarrow y=-x+11...(1)`

`\Rightarrow Slope =-1 \ldots (2)`

Since, `{AB}` is perpendicular to `x+y-11=0`


`\therefore` product of their slopes` =-1`

`\Rightarrow-1+` Slope of `A B=-1`

`\Rightarrow` Slope of `A B=1`

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