Find the equation of the parabola, if the focus is at `(-6,-6)` and the vertex is at `(-2, 2)`

Explanation

We have given focus as `(−6,−6)` and vertex as` (−2,2)`

Let `(-6,-6)`=F, `(-2,2)`=S

Then the slope of FS `=(−6−2)/(−6+2)=2`

Now let EZ be the directrix.

As, directrix is perpendicular to FZ.

Then the slope of directrix is −1/2
And the coordinates of the foot of the directrix Z be `(h,k)`.

As, A is mid-point of FZ.
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