Find the vertex , focus, axis, directrix and latus rectum of the following parabola: `4x^2+y=0`

Explanation

Given parabola equation is `4x^2+y=0`

Then we have

`X^2=-Y/4`

Now on comparing this equation with `X^2=−4ay`we get

`​4a=1/4⇒a=1/16`

Therefore vertex `=(X=0,Y=0)=(x=7/4,y=−2)`

And focus `=(x=0,y=−1/16)`

Now equation of directrix

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