Find the vertex , focus, axis, directrix and latus rectum of the following parabola: `y^2+4x+4y-3=0`

Explanation

Given parabola equation is `Y^2+4y+4x−3=0`

`(y+2)^2−4+4x−3=0`

`(y+2)^2=−4(x−7/4)`

Let `Y=y+2,X=x−7/4`

Then we have

`Y^2=4x`

Now on comparing this equation with `Y^2=−4ax`we get

`​4a=4⇒a=1`

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