Find the vertex , focus, axis, directrix and latus rectum of the following parabola: `y^2=8x+8y`

Explanation

`(y-4)^2=8(x+2)`

Putting `Y=y-4`

`X=x+2`

`Y^2=8X`

On comparing the given equation with `Y^2=4aX`

`4a=8=>a=2`

`` Vertex`=(X=0, Y=0)=(x=-2, y=4)`

Focus`=(X=a, Y=0)=(x+2=2, y-4=0)=(x=0, y=4)`
...