At what point of the parabola `x^2=9y` is the abscissa three times that of ordinate?

Explanation

To find the point on the parabola \( x^2 = 9y \) where the abscissa (x-coordinate) is three times the ordinate (y-coordinate), we can follow these steps:

### Step 1: Define the relationship between abscissa and ordinate
Let the ordinate be represented as \( A \). According to the problem, the abscissa is three times the ordinate. Therefore, we can express the abscissa as:
\[ x = 3A \]
and the ordinate as:
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