Find the equation of the ellipse whose axes are along the coordinate axes, foci at `(0,pm4)` and eccentricity 4/5.

Explanation

To find the equation of the ellipse whose axes are along the coordinate axes, with foci at (0, ±4) and eccentricity \( \frac{4}{5} \), we can follow these steps:

### Step 1: Identify the type of ellipse
Since the foci are located at (0, ±4), the ellipse is vertical. The standard form of the equation for a vertical ellipse is given by:

\[ \frac{x^2}{a^2} + \frac{y^2}{b^2} = 1 \]
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