Find the equation of the ellipse in the following case: eccentricity `e=2/3` and length of latus rectum `=5` .

Explanation

let the equation of the ellipse be `x^2/a^2 +y^2/b^2 =1`


Given that `e=2/3` and latus rectum =5


`:.( 2b^2)/(a) = 5`


`b^2 =(5a)/(2)`


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