Find the centre, the lengths of the axes, eccentricity, foci of the following ellipse: `4x^2+16 y^2-24 x-32 y-120=0`

Explanation

by rearranging the equation we get


` ((x-3)^2/43 +(y-1)^2/43/4)=1`

we get centre `=(3,1)`


also eccentricity =`sqrt((a^2-b^2)/a^2)`


we get ` e=sqrt3/2`
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