Find the equation of an ellipse with its foci on y-axis, eccentricity `3/4` , centre at the origin and passing through (6,4).

Explanation

we know that eccentricity of the ellipse is


`e=sqrt((a^2-b^2)/a^2)`


by putting ` e=3/4` and solving we get ` a^2=(7b^2)/16`


also by substituting the values `(6,4)` in the ellipse standard equation we get


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