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The directrix of the parabola x^2-4x-8y ...

The directrix of the parabola `x^2-4x-8y + 12=0` is

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Given
`x^{2}-4 x-8 y+12=0 `
`Rightarrow(x-2)^{2}-4-8 y+12=0 `
`Rightarrow(x-2)^{2}=8 y-8 `
`Rightarrow(x-2)^{2}=8(y-1) `
Putting ` X=x-2, Y=y-1`
`X^{2}=8 Y` Comparing with ` X^{2}=4 a Y a=2 `
Equation of the directrix `Y=-a `
...
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