The equation of the circle drawn with the two foci of `x^2/a^2+y^2/b^2=1` as the end-points of a diameter is

Explanation

`x^{2}+y^{2}=a^{2}-b^{2}`


We have `r=` `ae`


equation of the circle be `x^{2}+y^{2}=r^{2}`.


Now, `x^{2}+y^{2}=a^{2} e^{2}(therefore r=a e)`
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