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If (2,4) and (10,10) are the ends of a latus rectum of an ellipse with eccentricity then the length of semi major axis is a.`20//3` b. `15//3` c. `40//3` d. none of these

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Latus rectum=`{2b^2}/a`
`therefore{2b^2}/a =sqrt{(2-10)^2+(4-10)^2}`
`implies b^2=5a`
As `b^2=a^2(1-e^2)`
`implies 5a=a^2(1-(1/2)^2)`
`implies a=20/3`
Hence, length of semi-major axis is `20/3`
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