Home
Class 12
CHEMISTRY
The element chromium crystallises in a b...

The element chromium crystallises in a body centred cubic lattice whose density is `7.20g//cm^(3)`. The length of the edge of the unit cell is 288.4 pm. Calculate Avogadro's number (Atomic mas of Cr = 52).

Promotional Banner

Similar Questions

Explore conceptually related problems

Chromium crystallizes in a body centred cubic lattice, whose density is 7.20 g//cm^3 . The length of the edge of unit cell is 288.4 pm. Calculate Avogadro's number. (Atomic mass of chromium=52)

Chromium crystallizes in a body centred cubic lattice whose density is 7.20g/cm^3 . The length of the edge of the unit cell is 288.4 pm. Calculate the Avogadro number (atomic mass of chromium=52).

An element crystallizes as body - centred cubic lattic. Its density is 7.12g cm^(-3 and the length of the side of the unit cell is 2.88Å . Calculate the number of atoms present is 288g of the element.

An element crystallizes as body - centred cubic lattic. Its density is 7.12g cm^(-3 and the length of the side of the unit cell is 2.88Å . Calculate the number of atoms present is 288g of the element.

The radius of chromium atom is 1.25Å . If it crystallises in body centred cubic lattice, calculate the length of the edge of the unit cell.

The radius of chromium atom is 1.25Å . If it crystallises in body centred cubic lattice, calculate the length of the edge of the unit cell.

The radius of chromium atom is 1.25Å . If it crystallises in body centred cubic lattice, calculate the length of the edge of the unit cell.

Silver crystallises in a face-centred cubic unit cell. The density of Ag is 10.5 g cm^(-3) . Calculate the edge length of the unit cell.