A particle moves with deceleration along a circle of radius R so that at any moment its tangential and normal accelerations are equal in moduli. At the initial moment `t=0` the velocity of the point equals `v_(0)`. Find (a) the velocity of the point as a function of t and s , (b) the resultant acceleration modulus as a function of `v`.

A point moves with decleration along the circle of radius R so that at any moment of time its tangential and normal accelerations are equal in moduli. At the initial moment t=0 the velocity of the point equals v_0 . Find: (a) the velocity of the point as a function of time and as a function of the distance covered s_1 , (b) the total acceleration of the point as a function of velocity and the distance covered.

A point moves with decleration along the circle of radius R so that at any moment of time its tangential and normal accelerations are equal in moduli. At the initial moment t=0 the velocity of the point equals v_0 . Find: (a) the velocity of the point as a function of time and as a function of the distance covered s_1 , (b) the total acceleration of the point as a function of velocity and the distance covered.

A particle moves with deceleration along the circle of radius R so that at any moment of time its tangential and normal acceleration are equal in moduli. At the initial moment t=0 the speed of the particle equals v_(0) , then th speed of the particle as a function of the distance covered S will be

A particle moves with deceleration along the circle of radius R so that at any moment of time its tangential and normal acceleration are equal in moduli. At the initial moment t=0 the speed of the particle equals v_(0) , then th speed of the particle as a function of the distance covered S will be

A particle moves with deceleration along the circle of radius R so that at any moment of time its tangential and normal acceleration are equal in moduli. At the initial moment t=0 the speed of the particle equals v_(0) , then th speed of the particle as a function of the distance covered S will be

A particle moves with deceleration along the circle of radius R so that at any moment of time its tangential and normal acceleration are equal in moduli. At the initial moment t=0 the speed of the particle equals V_(0) then The speed of the particle as a function of the distance coverd will be

A particle moves with deceleration along the circle of radius R so that at any moment of time its tangential and normal acceleration are equal in moduli. At the initial moment t=0 the speed of the particle equals V_(0) then The total acceleration of the particle as function of velocity and distance covered

A particle moves with decreasing speed along the circle of radius R so that at any moment of time its tangential and centripetal accelerations are equal in magnitude. At the initial moment , t =0 its speed is u. The magnitude of tangential acceleration at t = R/(2u) is

A particle moves with decreasing speed along the circle of radius R so that at any moment of time its tangential and centripetal accelerations are equal in magnitude. At the initial moment , t =0 its speed is u. The magnitude of tangential acceleration at t = R/(2u) is