Evaluate the following limit: `underset( x rarr 0) ( "lim")((a+x)^2-a^2)/x`

Explanation

Given,

`(lim)_(x->0)((a+x)^2−a^2)/x`

`=(lim)_(x->0)((a+0)^2−a^2)/0`

`=0/0`

thus,

applying L-Hospital rule,


`(lim)_(x->0)((a+x)^2−a^2)/x`

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