Evaluate the following limit: `lim_(x->-1//2)(8x^3+1)/(2x+1)`

Explanation

Given limit: `(lim)_(x->-1//2)(8x^3+1)/(2x+1)`
>Substituting `-1/2` as we get an indeterminant form of `(0/0)`
As it has come back as `(0/0)` form , so we have a tendency to use L’Hospitals Rule.
now by victimization L’Hospitals Rule the limit is given by,
`l= lim_(x->-1//2)(24 x^2)/2`
`=12*(1/4)`
`=3`