If `lim_(x->a) (x^5-a^5)/(x-a)=5`, then find the sum of theIf lim-possible real values of a.

Explanation

Given that, If `lim_(x->a)(x^5-a^5)/(x-a)=5\ `
we have to find the real value of `a`.
by using formula ,
`lim_(x->a)(x^n-a^n)/(x-a) = n*a^(n-1)`
so, `lim_(x->a)(x^5-a^5)/(x-a)=5*a^4`
according to question `lim_(x->a)(x^5-a^5)/(x-a)=5`
so,` 5*a^4=5`
`a=+1 or -1`
The sum is `1-1=0`