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Evaluate the following limit: lim(x->0)(...

Evaluate the following limit: `lim_(x->0)(log(2+x)+log0.5)/x`

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`lim_(x->0)(log(2+x)+log0.5)/x`
Now apply L- Hospital Rule
`=(lim)_(x->0)(d/(dx)(log(2+x)+log0.5))/(d/(dx)(x))`
`=(lim)_(x->0)1/(2+x)`
`=1/2`
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