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Write the value of lim(x->oo)(sin x\ )/x...

Write the value of `lim_(x->oo)(sin x\ )/x`

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`lim_(x->oo)(sin x )/x`
Here if we put limits we get
`=(sin oo)/(oo) `
And we know that sin x is a periodic function ,
`implies -1 <=sinx<=1`
`implies sin (oo) in [-1,1]`
Then
`lim_(x->oo)(sin x )/x=[-1,1]/(oo)`
...
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