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lim(theta->pi//2)(1-sintheta)/((pi//2-th...

`lim_(theta->pi//2)(1-sintheta)/((pi//2-theta)costheta)` is equal to a. 1 b . -1 c. 1/2 d. -1/2

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`lim_(theta->pi//2)(1-sintheta)/((pi//2-theta)costheta)`
Apply L-Hospital Rule
Then
`=lim_(theta->pi//2)(d/(dx)(1-sintheta))/(d/(dx)((pi//2-theta)costheta))`
`=lim_(theta->pi//2) (-cos theta)/((-1)cos theta+(pi/2-theta)(-sin theta))`
`=lim_(theta->pi//2) ((-cos theta)/(cos theta))/(((-1)cos theta+(pi/2-theta)(-sin theta))/(cos theta))`
`=lim_(theta->pi//2) 1/(1+(pi/2-theta)tan theta)`
`=1`
...
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