Let `f` be a real valued function defined by `f(x)=x^2+1.` Find `f'(2)`.

Explanation

We have given the function `x^2+1` ,

Then `f(x)=x^2+1`

Then `f′(x)=2x`

`f′(2)=2(2)`

`f′(2)=4`

Hence, the derivative of the function `x^2+1` a t `x=2`is `4`.