Find the derivative of `f(x)=2x^2+3x-5` at `x=-1`. Also, prove that `f'(0)+3f'(-1)=0.`

Explanation

We have given the function `2x^2+3x-5` ,

Then `f(x)=2x^2+3x-5`

Then `f′(x)=4x+3`

`f′(−1)=4(−1)+3=−1`

`f′(0)=4(0)+3=3`

`f′(0)+3f′(−1)=3−3=0`

Hence, the derivative of the function `2x^2+3x-5` at `x=-1`is `4x+3`

and `f′1(0)+3f′1(−1)=0`is proved .