The distance `f(t)` in metres ived by a particle travelling in a straight line in `t` seconds is given by `f(t)=t^2+3t+4`. Find the speed of the particle at the end of 2 seconds.

Explanation

We have given ,

`f(t)=t^2+3t+4`

So, the speed of the particle is given by

`v=(ds)/dt`

`v=(d(f(t)))/dt`

`v=f'(t)`

At the end of 2 second,

`v=f'(2)`

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