Find the slope of the tangent to the curve `y=x^2` at `(-1/2,1/4)`.

Explanation

We have given the equation of curve is,

`y=x^2`

Thus, slope of tangent to the curve is given by,

`m=dy/dx`

so,`m=(d(x^2))/dx`

hence,`m=2x`

Slope of tangent at point `(-1/2,1/4)` is,

`m=2×(-1/2)`

...