Differentiate the following with respect of `x :2secx+3cotx-4tanx`

Explanation

Glven

`f(x)=2 sec x+3 cot x-4 tan x`

`therefore frac{d}{d x}{f(x)}=frac{d}{d x}(2 sec x+3 cot x-4 tan x)`

algebra of derivatives -

`Rightarrow f^{prime}(x)=2 frac{d}{d x}(sec x)+3 frac{d}{d x}(cot x)-4 frac{d}{d x}(tan x)`

formula:

`frac{{d}}{{dx}}(cot {x}) =-{cosec}^{2} {x}, frac{{d}}{{dx}}(sec {x}) `

`=sec {x} tan {x} frac{{d}}{{dx}}(tan {x}) `

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