Differentiate the following function with respect of `x :(e^x)/(1+x^2)`

Explanation

Let u=`e^x`

so `(du/dx)=e^x`

`v=1+x^2`

`(dv/dx)=2x`

So `(dy/dx)=(v(du/dx)-u(dv/dx))/v^2`

Putting vales we get,
`(dy/dx)=e^x(x^2-2x+2)/(x+1)^2`