Differentiate the following function with respect of `x :(x^5-cos x)/(sinx)`

Explanation

`y =( x^5−cos x)/sin x`



`(dy/dx)=(sin x(d/dx)(x^5−cos x)−(x^5−cos x)(d/dx)sin x)/(sin x)^2` [by quotient rule]


=`(sin x(5x^4+sin x)−(x^5−cos x))/sin^2x`

=`(5x^4sin x+sin^2x−x^5cos x+cos^2x)/sin^2x
`

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