A body of density `rho` is released gently on the surface of a layer of liquid of depth d and density `rho'(rho' lt rho)` . Show that it will reach the bottom of the liquid after a time.
`[(2 d rho)/(g(rho-rho'))]^(1//2)` .

(a). Discuss two situations in daily life where we apply the concept of pressure. (b). A body of density rho is dropped gently on the surface of a liquid of density rho' (rho' being less than rho ). Show That it will reach the bottom of the liquid after a time sqrt((2drho)/(g(rho-rho'))) , where g is acceleration due to gravity and d is the depth of the liquid.

A body of density rho is placed slowly on the surface of a liquid of density delta . If the depth of the liquid is d, then prove that the time taken by the body to reach the bottom of the liquid is [(2drho)/g(rho-delta)]^(1//2) second.

A ball of density rho is released from deep inside of a liquid of density 2 rho . It will move up

A ball of density rho is released from deep inside of a liquid of density 2 rho . It will move up

A ball of density rho is dropped from a height on the surface of a non-viscous liquid of density 2rho . Choose the correct options.

The pressure at depth h below the surface of a liquid of density rho open to the atmosphere is

The pressure at depth h below the surface of a liquid of density rho open to the atmosphere is

The pressure inside a liquid of density rho at a depth h is :