Show that the following statement is true by the method of contrapositive `p : if\ x` is an integer and `x^2` is odd then `x` is also odd.

Explanation

If `x^2` is odd then x is odd


now becomes


If `x^2` is even thenx is even


which is the contrapositive, the idea is that if we can
prove that `x^2` is even for allx that is even, it stands
to reason that `x^2` can only be odd for all x that is odd.


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