Calculate the mean deviation from the mean for the following data:36,72,46,42,60,45,53,46,51,49

Explanation

Given
`36,72,46,42,60,45,53,46,51,49`

` n = 10`

median `=(46+49)/2​=(95)/2​=47.5`

mean deviation above median =
`((136−47.51+142−47.51+145−47.51+146−47.51+146−47.51+149−47−51+151−47.51+153−47.51+160−47.51+172−47.51))/(10)​`

`= (11.5+5.5+2.5+1.5+1.5+1.5+3.5+5.5+12.5+24.5​)/(10)`

`= (70)/(10)​=7`