समतल  `vecr.(6hati - 3hatj - 2hatk) + 1=0` पर मूल बिंदु से डाले गए लंब इकाई सदिश की दिक्-कोसाइन ज्ञात कीजिए।

If the point of intersection of the line vecr = (hati + 2 hatj + 3 hatk ) + lambda( 2 hati + hatj+ 2hatk ) and the plane vecr (2 hati - 6 hatj + 3 hatk) + 5=0 lies on the plane vec r ( hati + 75 hatj + 60 hatk) -alpha =0, then 19 alpha + 17 is equal to :

If the point of intersection of the line vecr = (hati + 2 hatj + 3 hatk ) + ( 2 hati + hatj+ 2hatk ) and the plane vecr (2 hati - 6 hatj + 3 hatk) + 5=0 lies on the plane vec r ( hati + 75 hatj + 60 hatk) -alpha =0, then 19 alpha + 17 is equal to :

Find the angle between the folowing planes :- (i) vecr.(2hati-3hatj+4hatk) = 5 and vecr.(-hati+hatj) = 1 (ii) vecr.(2hati+3hatj-6hatk) = 1 and vecr.(hati-2hatj+2hatk) + 3 = 0 (iii) x+y-2z=3 and 2x-2y+z+1 = 0 (iv) x+y-z=8 and -x+2y+z-1 = 0

Find the equation of the plane which contains the line of intersection of the planes vecr cdot(hati+2hatj+3hatk) - 4 = 0 and vecr cdot (2hati + hatj - hatk) +5 = 0 and which is perpendicular to the plane vecr cdot (5hati+3hatj-6hatk) +8 =0

Find the shortest distance between the lines l_(1)and l_(1) whose vector equations are vecr=(hati+hatj) + lambda (3hati + 4hatj - 2hatk) …(i) and vecr=(2hati+3hatj) + mu (6hati + 8hatj - 4hatk) …(ii)

Find the shortest distance between the lines l_(1)and l_(1) whose vector equations are vecr=(hati+hatj) + lambda (3hati + 4hatj - 2hatk) …(i) and vecr=(2hati+3hatj) + mu (6hati + 8hatj - 4hatk) …(ii)

If vecF=2hati+3hatj-hatk and vecr=hati-hatj+6hatk find vecrxxvecF

The line of intersection of the planes vecr . (3 hati - hatj + hatk) =1 and vecr. (hati+ 4 hatj -2 hatk)=2 is:

Find the equation of the plane though the line of intersection of the planes vecr.(2 hati-3 hatj+ 4 hatk)=1 and vecr.( hati- hatj)+4=0 and prependicular to vecr.(2 hati- hatj+ hatk)+8=0 .

If vecr_(1)=hati+2hatj-2hatk and vecr_(2)=3hatj-4hatk , then the angle between vecr_(1) and vecr_(2) is -