Solve the equation `x^2-4x+13=0` by factorization method.

Answer

the roots of the given equation are `2+3 i` and `2-3 i`.

Explanation

Given equation is `x^{2}-4 x+13=0`



Comparing with `a x^{2}+b x+c=0`, we get



$$ a=1, b=4, c=13

$$
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