Solve the quadratic equation `2x^2-4x+3=0` by using the general expressions for the roots of a quadratic equation.

Answer

Roots are `frac{2+sqrt{2 i}}{2}, frac{2-sqrt{2 i}}{2}`

Explanation

$$
\begin{aligned}
&2 x^{2}-4 x+3=0 \\
&\text { Roots are } \frac{4 \pm \sqrt{16-4(3)(2)}}{2 x^{2}} \\
&=\frac{4 \pm \sqrt{16-24}}{4}=\frac{4 \pm \sqrt{-8}}{4} \\
&=\frac{4 \pm 2 \sqrt{2} i}{4} \\
&=\frac{2 \pm \sqrt{2} i}{2}
\end{aligned}
...