Solve the following quadratic equation by factorization method only: `\ x^2+2x+5=0`

Answer

The roots of the given equation are `-1+2 i,-1-2 i`

Explanation

Given as `x^{2}+2 x+5=0`
$$
\begin{aligned}
&x^{2}+2 x+1+4=0 \\
&x^{2}+2(x)(1)+1^{2}+4=0 \\
&(x+1)^{2}+4=0\left[\text { since },(a+b)^{2}=a^{2}+2 a b+b^{2}\right] \\
&(x+1)^{2}+4 \times 1=0
\end{aligned}
...