Solve the following quadratic equation by factorization method only: `\ 4x^2-12 x+25=0`

Answer

The roots of the given equation are `3 / 2+2 i, 3 / 2-2 i`

Explanation

Given as `4 x^{2}-12 x+25=0`
$$
\begin{aligned}
&4 x^{2}-12 x+9+16=0 \\
&(2 x)^{2}-2(2 x)(3)+3^{2}+16=0 \\
&(2 x-3)^{2}+16=0\left[\text { Since, }(a+b)^{2}=a^{2}+2 a b+b^{2}\right] \\
&(2 x-3)^{2}+16 \times 1=0
\end{aligned}
...