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Solve the following quadratic: 27 x^2-10...

Solve the following quadratic: `27 x^2-10 x+1=0`

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The correct Answer is:
Solution

`frac{5}{27} pm frac{sqrt{2}}{27} i`

The given quadratic equation is `27 x^{2}-10 x+1=0`

On comparing this equation with `ax^{2}+bx+c=0`,

we obtain `a=27, b=-10`, and `c=1`
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