Solve the following quadratic: `21 x^2-28 x+10=0`

Answer

`(x_{1}, x_{2})=frac{2}{3} pm frac{sqrt{14}}{21} i`

Explanation

The given quadratic equation is `21 x^{2}-28 x+10=0`


On comparing this equation with `a x^{2}+b x+c=0`,


we get `a=21, b=-28` and `c=10`
Therefore the discriminant of the given equation is
$$
\mathrm{D}=\mathrm{b}^{2}-4 \mathrm{ac}=(-28)^{2}-4 \times 21 \times 10=784-480=-56
...