Solve the following quadratic equation: `\ x^2-(5-i)x+(18+i)=0`

Answer

`x=2+3 i, 3-4 i`

Explanation

We apply the Quadratic Formula and get,


`x=((5−i)±√((5−i)^2−4(18+i)))/2` , i.e. ,




`x=((5−i)±{(25−10i−1)−72−4i})/2` , or ,




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