Solve the following quadratic equation: `\ 2x^2-(3+7i)x+(9i-3)=0` `alpha = 3/2 + (1/2)i` and `beta = 3i`

Answer

`x=3 i quad or quad x=(frac{i+3}{2})`

Explanation

Given can:- `2 x^{2}-(3+7 i) x+(9 i-3)=0`



` 2 x^{2}-(3+7 i) x-(3-9 i)=0`



we know that for `a x^{2}+b x+c=0` ep":-



`x=frac{-b pm sqrt{b^{2}-4 a c}}{2 a}`



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