If `a\ a n d\ b` are roots of the equation `x^2-x+1=0` then write the value of `a^2+b^2dot`

Answer

` {a}^{2}+{b}^{2}=-1`

Explanation

Sum of the roots` Rightarrow a+b=-1`

Product of the roots` Rightarrow a b=1`

We know that,



begin{aligned}

`(a+b)^{2}=a^{2}+b^{2}+2 a b`

`Rightarrow a^{2}+b^{2}=(a+b)^{2}-2 a b`



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