Find the `V_(ab)` in an electric field `E=(2hati+3hatj+4hatk)N/C`, where `r_a=(hati-2hatj+hatk)m` and `r_b=(2hati+hatj-2hatk)m`

Find the angle between the lines vecr = (2hati - hatj +3hatk) + lambda(hati + hatj + 2hatk) and vec r = (hati - 3hatj)+mu(2hatj - hatk)

The angle between the straight line r=(hati+2hatj+hatk)+lambda(hati-hatj+hatk) and the plane r.(2hati-hatj+hatk)=4 is

Find the distance between the lines vecr=3hati+2hatj-4hatk+lambda(hati+2hatj+2hatk) and vecr=5hati-2hatk+mu(hati+2hatj+2hatk)

The acute angle between the line r=(hati+2hatj+hatk)+lambda(hati+hatj+hatk) and the plane r.(2hati-hatj+hatk)=5

Find the shortest distance betwee the lines : vec(r) = (hati + 2 hatj + hatk ) + lambda ( hati - hatj + hatk) and vec(r) = 2 hati - hatj - hakt + mu (2 hati + hatj + 2 hatk) .

If a=3hati-2hatj+hatk,b=2hati-4hatj-3hatk and c=-hati+2hatj+2hatk , then a+b+c is

If a=3hati-2hatj+hatk,b=2hati-4hatj-3hatk and c=-hati+2hatj+2hatk , then a+b+c is

If a=3hati-2hatj+hatk,b=2hati-4hatj-3hatk and c=-hati+2hatj+2hatk , then a+b+c is