In a simultaneous toss of two coins, find the probability of getting: exactly 1 tails

Explanation

Getting one tail:


Let E2​ = event of getting 1 tail. Then,


E2​={TH,HT} and, therefore, n(E2​)=2.


Therefore, P(getting 1 tail) `=P(E2​)=(n(E2​))/(n(S))​=2/4​=0.5`