A fair coin with 1 marked on one face and 6 coin the other and a fair die are both tossed, fid the probability that the sum of numbers that turn up is i. 3 ii. 12.

Explanation

Since the fair coin has 1 marked on one face and 6 on the other and the die has six
faces that are numbered 1,2,3,4,5 and 6 the sample space is given by

S={(1,1),(1,2),(1,3),(1,4),(1,5),(1,6),(6,1),(6,2),(6,3),(6,4),(6,5),(6,6)}

⇒n(S)=12

(i) Let A be the event in which the sum of numbers that turn up is 3

⇒A={(1,2)}

∴`P(A)=(n(A))/(n(S))​=1/12`
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(ii) Let B be the event in which the sum of numbers that turn up is 12

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