In a single throw of three dice, determine the probability of getting i. total of 5 ii.  total of at most 5 ii. a total of at least 5.

Explanation

Simple space =6×6×6=216

Total outcomes =216

(i)Total of 5

a+b+c=5

(1,1,3),(1,3,1),(3,1,1),(1,2,2),(2,1,2),(2,2,1)

∴ probability `=6/216=1/36`
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(ii) A total of atmost 5=(1,1,1),(1,1,3),(1,3,1),(3,1,1),(1,2,2),(2,1,2),(2,2,1),(1,1,2),(2,1,1),(1,2,1)

∴ prob =`10/216​=5/108`
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