In a class of 60 students 30 opted for NCC, 32 opted for NSS and 24 opted for both NCC and NS. If one of these students is selected at random, find the probability that: i.                The student opted for NCC or NSS ii.              The student has opted NSS or NCC.

Explanation

Let `A` is the event for selecting `NCC`

`B` is the event for selecting `NSS`.

Then, .
`n(S)=60,n(A)=30,n(B)=32,n(A∩B)=24`.

So,` P(A)=30/(60)=1/2`.

`P(B)=32/(60)=8/(15)`.

`P(A∩B)=(24)/(60)=2/5`.

(i)Probability that the selected student opted for NCC or .NSS

`P(A∪B)=P(A)+P(B)−P(A∩B)`

...